4.9(t^2+7t-60)=0

Solution for 4.9(t^2+7t-60)=0 equation:

4.9(t^2+7t-60)=0

We multiply parentheses

4.9t^2+34.3t-294=0

a = 4.9; b = 34.3; c = -294;
Δ = b2-4ac
Δ = 34.32-4·4.9·(-294)
Δ = 6938.89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34.3)-\sqrt{6938.89}}{2*4.9}=\frac{-34.3-\sqrt{6938.89}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34.3)+\sqrt{6938.89}}{2*4.9}=\frac{-34.3+\sqrt{6938.89}}{9.8}
$